Determine the energy in joules of a photon whose frequency is 3.05 ✕ 10^17 Hz.

The energy of photon is 20.22×10⁻¹⁷ J

Explanation:

Given data:

Frequency of photon = 3.05×10¹⁷ Hz

Energy of photon = ?

Solution:

Formula:

E = hf

h = planck's constant = 6.63×10⁻³⁴ Js

Now we will put the values in formula.

E =   6.63×10⁻³⁴ Js × 3.05×10¹⁷ Hz

    Hz = s⁻¹

E = 20.22×10⁻¹⁷ J

Thus, the energy of photon is 20.22×10⁻¹⁷ J