Ice cube trays hold about 350 grams of water. If the water comes out of the faucet at 37 degrees celcius, how much evergy do I have to remove to freeze the ice cubes?

-171.79 KJ

Explanation:

We must keep in mind that water freezes at 0 degrees centigrade

Recall that heat lost during freezing can be obtained from;

H = mc(θ2 - θ1)

m = mass of the water = 350 g/1000 = 0.35 Kg

c = specific heat capacity of water = 4,200 J/kg°C

θ2 = final temperature = 0°C

θ1 = initial temperature = 37°C

H= 0.35 * 4,200 * (0 - 37)

H = -54390 J = -54.39 KJ

Energy given out when 1 mole of water freezes at its freezing point = -6.04 kJ

For 350 g of water; 350 g/18 g/mol *  -6.04 kJ  = -117.4 kJ

Hence total energy removed = (-54.39 KJ) + (-117.4 kJ) = -171.79 KJ

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explanation:

metals have excess of electrons whereas non-metals have deficiency of electrons. thus, in order to gain stability metals easily donate their electrons to the non-metals.

for example, electronic configuration of sodium is and electronic configuration of phosphorous is .

when a phosphorous atom and sodium atom combine together then sodium will donate is extra one electron to the phosphorous atom. as a result there will be formation of ionic bond between sodium and phosphorous.

the reaction will be as follows.

there, are three sodium sodium atoms and each of them will donate its one extra electron to phosphorous atom. thus, the sub-shell of phosphorous gets completely filled.  

thus, we can conclude that electrons are transferred from atoms of sodium to atoms of phosphorous. this transfer makes the sodium atoms donate one electron and the phosphorous atoms to gain one electron. as a result, the sodium and phosphorus atoms strongly attract each other.