If 0.0369 mol CaCl2 is dissolved in water to make a 0.340 M solution, what is the volume of the solution

The correct answer is 0.11 L

Explanation:

From the problem, we have the following data:

moles CaCl₂= 0.039 mol

molarity = 0.340 M = 0.340 mol CaCl₂/L

According to this, the solution has 0.340 mol of CaCl₂ in 1 L. If the total number of moles is 0.0369, we can find the volume as follows:

V= moles/molarity = 0.0369 mol x 1 L/0.340 mol = 0.108 L ≅ 0.11 L

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each  column  of the  table  is called a group. elements in a group share similar properties. groups are  read  from  top  to  bottom. metal. metalloid. nonmetal. solid. liquid. gas. fe. hg. o.  2. 3. 4. 5. 6. 7. 8. 9.  2. beryllium. 9.012. 4.  sodium. 22.990.  11. 3.  magnesium. 24.305.  12.  potassium. 39.098.  19. 4.  calcium. 40.078.  20. i guess  i