15.0 L of an ideal gas at 298 K and 3.36 atm are heated to 383 K with a new pressure of 5.60 atm. What is the new volume in liters

Explanation:

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In this case, since we volume, pressure and temperature which are all changing, we can use the combined ideal gas law to write:

Thus, since the final volume V2 is required, by solving for it, we write:

In such a way, we plug in the given data to obtain:

Which means that the process compressed the gas.

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n2(g) + 3h2-> 2nh3(g)   this is the balanced equation

note the mole ratio between n2, h2 and nh3.   it is 1 : 3 : 2   this will be important.

moles n2 present = 28.0 g n2 x 1 mole n2/28 g = 1 mole n2 present

moles h2 present = 25.0 g h2 x 1 mole h2/2 g = 12.5 moles h2 present

based on mole ratio, n2 is limiting in this situation because there is more than enough h2 but not enough n2.

moles nh3 that can be produced = 1 mole n2 x 2 moles nh3/mole n2 = 2 moles nh3 can be produced

grams of nh3 that can be produced = 2 moles nh3 x 17 g/mole = 34 grams of nh3 can be produced

note:   the key to this problem is recognizing that n2 is limiting, and therefore limits how much nh3 can be produced.