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Using the following equation: 2NH3 + 3Cl2 --> N2 + 6HCl if you had 0.653 mol of HCl gas produced, how many g of ammonia gas was used?
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Using the following equation: 2NH3 + 3Cl2 --> N2 + 6HCl
if you had 0.653 mol of HCl gas produced...
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