If 50.9 g of aspirin (C₉H₈O₄) are produced from 79.8 g of C₇H₆O₃, what is the percent yield from the reaction below? C₇H₆O₃ (s) + C₄H₆O₃ (s) → C₉H₈O₄ (s) + HC₂H₃O₂ (aq).

This may or may not be right its been a while since I took chemistry but 63.78%

Explanation:

The yield is 50.9 so you would divide the yield by the source.

50.9/79.8= .637844621

than conver that to a percentage and you have your answer I think.

May or may not be right like I said it's been a while but I hope its right and it helps.

48.9%

Explanation:

I'm in Chemistry right now, so my mind is a bit more fresh on this.

Convert the mass of C₇H₆O₃ to moles

79.8 gC₇H₆O₃ x 1 mol C₇H₆O₃ / 138.12 gC₇H₆O₃ = 0.5578 mol C₇H₆O₃

Then get the theoretical yield of aspirin

0.5778 mol C₇H₆O₃ x 1 mol C₉H₈O₄ / 1 mol C₇H₆O₃ = 0.5778mol  C₉H₈O₄

Now the mass of the actual yield to moles

50.9 g C₉H₈O₄ x 1 mol g C₉H₈O₄ / 180.16 g C₉H₈O₄ = 0.2825 mol C₉H₈O₄

Now time for the answer! To get percent yield do actual yield/theoretical yield

0.2825 mol C₉H₈O₄ / 0.5778mol  C₉H₈O₄ x 100 = 48.9%