A sample of a gas in an 11.2 L container is at 1.0 atm and 0°C, as shown. The mass of the sample is 16 g Which of the following is most likely to be the identity of the gas, and why? SOs, because there is 0.25 mol of gas in the container and the mass of 0.25 mol of SO, is 16 %
Oz, because there is 0.50 mol of gas in the container and the mass of 0.50 mol of O, is 16 g
CH, because there is 1.0 mol of gas in the container and the mass of 1.0 mol of CH is 16
He, because there are 4.0 mol of gas in the container and the mass of 4.0 mol of He is 16g

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g

a  solution  is always transparent, light passes through with no scattering from solute particles which are molecule in size. the  solution  is homogeneous and does not settle out. a colloid is intermediate between asolution  and a  suspension. while asuspension  will separate out a colloid will not.

hurricanes form in warm water