1. If a solution of sodium chloride has 22.3 g of NaCl, and a volume of 2.00 L, what is its molarity?

We are given:

Mass of NaCl in the given solution = 22.3 grams

Volume of the given solution = 2 L

Number of Moles of NaCl:

We know that the number of moles = Given mass / Molar mass

Number of moles = 22.3 / 58.44 = 0.382 moles

Molarity of NaCl in the Given solution:

We know that Molarity of a solution = Moles of Solute / Volume of Solution(in L)

Molarity = 0.382 / 2

Molarity = 0.191 M

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explanation:

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