Net ionic equation of HF(aq)+RbOH(aq)=H2O(l)+RbF(aq)

net ionic equation

H⁺(aq)+OH⁻(aq)⇒H₂O(l)

The electrolyte in the solution produces ions.  

The equation of a chemical reaction can be expressed in the equation of the ions  

For strong electrolytes (the ionization rate = 1) is written in the form of separate ions, while the weak electrolyte (degree of ionization <1) is still written as an un-ionized molecule  

In the ion equation, there is a spectator ion that is the ion which does not react because it is present before and after the reaction  

When these ions are removed, the ionic equation is called the net ionic equation  

For gases and solids including water (H₂O) can be written as an ionized molecule  

So only the dissolved compound is ionized ((expressed in symbol aq)  

Reaction

HF(aq)+RbOH(aq)⇒H₂O(l)+RbF(aq)

ionic equation

H⁺(aq)+F⁻(aq)+Rb⁺(aq)+OH⁻(aq)⇒H₂O(l)+Rb⁺(aq)+F⁻(aq)

net ionic equation

H⁺(aq)+OH⁻(aq)⇒H₂O(l)

d: the voltage of the secondary coil is less than that of the primary coil.

im not suree sorry if wrong

m=9

step-by-step explanation: