Chemistry, 11.11.2020 17:20 StrawberryCake24
Aluminum hydroxide reacts with sulfuric acid as follows: 2Al(OH)3+3H2SO4âAl2(SO4)3+6H2O. Which reagent is the limiting reactant when 0.550 mol Al(OH)3 and 0.550 mol H2SO4 are allowed to react?How many moles of Al2(SO4)3 can form under these conditions? How many moles of the excess reactant remain after the completion of the reaction?
Answers: 1
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Aluminum hydroxide reacts with sulfuric acid as follows: 2Al(OH)3+3H2SO4âAl2(SO4)3+6H2O. Which reage...
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