Chemistry, 10.11.2020 20:10 StephenSudu
A 50.0 ml sample of 0.200 M HNO2 (weak acid) is titrated with 0.400 M
KOH. Calculate the pH after addition of 25 ml KOH (Ky for HNO, is 4.6 x
10-4)
O a 6.67
O b. 7.67
O c.8.23
O d. 9.12
Answers: 2
![\tt [OH^-]=\sqrt{\dfrac{Kw}{Ka}.M }](/tpl/images/0884/8776/41931.png)
![\tt [OH^-]=\sqrt{\dfrac{10^{14}}{4.6\times 10^{-4}} }\times 0.133\\\\(OH^-)=1.7\times 10^{-6}\\\\pOH=6-log~1.7=5.77\\\\pH+pOH=14\\\\pH+5.77=14\\\\pH=8.23](/tpl/images/0884/8776/d039c.png)
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A 50.0 ml sample of 0.200 M HNO2 (weak acid) is titrated with 0.400 M
KOH. Calculate the pH after a...
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