The volume of a gas decreases to half of its original volume, but the gas maintains the same number of moles and temperature. According to the ideal gas law, what will most likely happen to the pressure? It will double. It will decrease. It will increase slightly. It will remain the same.

It will double

Explanation:

Given;

From the ideal gas equation;

PV = nRT

P=nRT/V

where;

P = pressure of the gas

n= number of moles of the gas

V= volume of the gas

R = the gas constant

T= absolute temperature of the gas

If V is halved when n and T remain the same

P2 = nRT/V/2

P2 = nRT * 2/V

P2 = 2nRT/V

Hence the pressure is doubled.

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