Write the net ionic reaction for the following double replacement reaction: CuSO4(aq) + Na2S(aq) → CuS(s) + Na2SO4(aq)

Net ionic equation

Cu²⁺(aq)+S²⁻(aq)⇒CuS(s)

Double-Replacement reactions. Happens if there is an ion exchange between two ion compounds in the reactant to form two new ion compounds in the product

In the ion equation, there is a spectator ion that is the ion which does not react because it is present before and after the reaction  

When these ions are removed, the ionic equation is called the net ionic equation  

For gases and solids including water (H₂O) can be written as an ionized molecule  

Reaction

CuSO₄(aq)+Na₂S(aq)⇒CuS(s)+Na₂SO₄

ionic equation

Cu²⁺(aq)+SO₄²⁻(aq)+2Na⁺(aq)+S²⁻(aq)⇒CuS(s)+2Na⁺(aq+SO₄²⁻(aq)

spectator ions : 2Na⁺ and SO₄²⁻

Net ionic equation

Cu²⁺(aq)+S²⁻(aq)⇒CuS(s)

it should be p1 v1 = p2 v2

thats a little if u want the answer just look it up on google thats what i do haha : )