The Molar Mass (g/mol) of an ideal gas whose density is 2.5g/L at 1.8 atm and 30,0 Celsius ? 35 g/mol
64 g/mol
44 g/mol
38 g/mol

M = 35 g/mol

Explanation:

Given data:

Density = 2.5 g/L

Pressure = 1.8 atm

Temperature = 30°C (273.15 +30 = 303.15 K)

Molar mass = ?

Solution:

d = PM/RT

M = dRT/P

M =  2.5 g/L × 0.0821 atm.L/mol.K ×  303.15 K / 1.8 atm

M = 62.22 atm. g/mol/ 1.8 atm

M = 35 g/mol