Consider this initial-rate data at a certain temperature for the reaction described by n2o3(
g. -> no(
g. + no2(
g. n2o3 (m) = .1 (initial rate= .66) = .2 (initial rate= 1.32) = .3 (initial rate= 1.98) find k ?

N2O3(g)→NO(g)+NO2(g)

[N2O3] Initial Rate
0.1 M     r(t)=0.66 M/s
0.2 M     r(t)=1.32 M/s
0.3 M     r(t)=1.98 M/s

We can have the relationship:

([N2O3]/[N2O3]0)^m=r(t)/r0(t)
However,
([N2O3]/[N2O3]0) = 2

Also, we assume m=1 which is the order of the reaction.

Thus, the relationship is simplified to,

r(t)/r0(t) = 2

r(t)=k[N2O3]

0.66 M/s=k×0.1 M

k=6.6 s−1

i think it is d. e because the next one is igneous.

there is none because earth is stationary and flat.