How many ml of a 0.175 m fecl3 solution are needed to make 250. ml of a solution that is 0.300 m in cl- ion? can ya'll explain how to find the answer to this?

The volume of FeCl₃ needed to make 250 mL of 0.3 M in Cl⁻ ions was 142,857 ml

Dilution is the process of adding solvents (generally water) which aims to obtain a solution with a concentration that is smaller than the initial concentration of a more concentrated substance.

So the principle of dilution is to get a lower / dilute concentration.

At dilution the number of dissolved moles before and after dilution is the same

The dilution formula is as follows:

M1 = Molarity of the solution before dilution

V1 = Volume of solution before dilution

M2 = Molarity of solution after dilution

V2 = Volume of Molarity of solution after dilution

Ionization reaction on FeCl₃

FeCl₃ -> Fe³⁺ + 3Cl⁻

For 0.175 M FeCl₃ there are 3.0,175 M Cl⁻ = 0.525 M Cl⁻

Because what is needed is a 250 ml 0.3 M Cl⁻ solution, then we use the dilution formula:

M1V1 = M2V2

0.525. V1 = 250. 0.3

V1 = 142,857 ml

Moles of NaOH are present in 25.0 mL of a 0.1000 M NaOH solution

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A 25.00 ml sample of h3po4 solution

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hydrogen and excess oxygen

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Keywords: Cl- ion, Molarity, FeCl3, solution

the answer is the first option

explanation:

just googled it m8. not that hard

lol