Please help! Explain how the rate of diffusion of a gas is related to its molar mass.

Carbon dioxide gas (CO2) effuses 3.2 times faster than an unknown gas. Determine the molar mass of the unknown gas. Show your work or explain your answer, giving specific values used to determine the answer.

450.56

Explanation:

From Graham's law of diffusion;

R1 /R2 = √M.M2 /√M.M1

R1 = rate of diffusion of the first gas which is CO2

R2 = rate of diffusion of the second gas which is the unknown gas

M.M1 = molar mass of the first gas (CO2) = 44

M.M2 = molar mass of the second gas =?

R1/R2 = 3.2

Substituting all the values into the equation as follows:

3.2 = √M.M2 /√44

Squaring both sides;

3.2^2 = M.M2 / 44

Cross multiply as follows;

M.M2 = 3.2*3.2*44

= 450.56

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the correct answer is:

a. formation of precipitation