How many milliliters of a 3.4 M NaCl solution would be needed to prepare each solution? a. 45 mL of a 0.10 M solution:
mL

b. 330 mL of a 0.074 M solution:
mL

a. Approximately .

b. Approximately .

Explanation:

The unit of concentration "" is equivalent to "", which means "moles per liter."

However, the volume of both solutions were given in mililiters . Convert these volumes to liters:

.

.

In a solution of volume where the concentration of a solute is , there would be (moles of) formula units of this solute.

Calculate the number of moles of formula units in each of the two solutions:

Solution in a.:

.

Solution in b.:

.

What volume of that (same as ) solution would contain that many

For the solution in a.:

.

Convert the unit of that volume to milliliters:

.

Similarly, for the solution in b.:

.

Convert the unit of that volume to milliliters:

.

the correct answer is b. a strong acid completely dissociates to its ions when dissolved in water. completely dissociates to and ions. a is incorrect because does not fully ionize to and ions and some remain as the compound . c and d are incorrect because, and do not fall into the category of bronsted lowry acids. a bronsted lowry acid is a proton donor and since both molecules do not have a proton to donate they are not bronsted lowry acids. likewise,   if we use the lewis acid definition, they cannot be acids. a lewis acid is an electron pair acceptor. both and have a complete octet so can not accept any electrons which disqualifies them as acids.