2.00 g of an unknown gas at STP fills a 500. mL flask. What is the molar mass of the gas?

The molar mass of the unknown gas in the 500 mL flask at stp is 89.7 g/mol

We'll begin by calculating the number of mole of the gas that occupied 500 mL at stp.

Recall at stp:

22400 mL = 1 mole of the gas

Therefore,

500 mL = 500 / 22400 = 0.0223 mole of gas.

Finally, we shall determine the molar mass of the gas. This can be obtained as follow:

Mass of gas = 2 g

Mole of gas = 0.0223 mole

Molar mass = mass / mole

Molar mass of gas = 2 / 0.0223

Therefore, the molar mass of the unknown gas is 89.7 g/mol

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100g/mol

Explanation:

Given parameters:

Mass of unknown gas  = 2g

Volume of gas in flask  = 500mL  = 0.5dm³

Unknown:

Molar mass of gas = ?

Solution:

Since we know the gas is at STP;  

        1 mole of substance occupies 22.4dm³ of space at STP

    Therefore,

            0.5dm³ will have  0.02mole at STP

Now;

   Number of moles  =  

      Molar mass  =   =   = 100g/mol

in 1783 cavendish was working with his hydrogen gas and found that when he burned it and condensed the vapor it was water. this was very significant since it disproved the greek theory of elements completely since water was not a simple substance but the product of two gases. it was lavoisier who hearing of the experiment gave cavendish's gas the name hydrogen ("water-producer") and added that hydrogen burned by combining with oxygen and that water was a hydrogen-oxygen combination.

explanation:

consider the reaction below.

 no rx

at 500 k, the reaction is at equilibrium with the following concentrations.

[pci5]= 0.0095 m

[pci3] = 0.020

[ci2] = 0.020 m

what is the equilibrium constant for the given reaction?

0.042

0.42

2.4

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