What mass in grams of MgSO4 is required to make 59.3 mL of 2.68 M
solution?

Approximately .

Explanation:

The unit of concentration in this question is "". That's equivalent to "" (moles per liter.) In other words:

.

However, the unit of the volume of this solution is in milliliters. Convert that unit to liters:

.

Calculate the number of moles of formula units required to make this solution:

.

Look up the relative atomic mass data of , , and on a modern periodic table:

Calculate the formula mass of using these values:

.

Using this formula mass, calculate the mass of that (approximately) of formula units:

.

Therefore, the mass of required to make this solution would be approximately .

oxygen, selenium, tellurium, and polonium.

they're all from the same group as sulfur (group 16).

answer; 4 electrons;