A solution is prepared at 25°C that is initially 0.43M in acetic acid HCH3CO2 , a weak acid with =Ka×1.810−5 , and 0.10M in sodium acetate NaCH3CO2 . Calculate the pH of the solution. Round to 2 decimal places.

Density and pressure

The answer for this is a

Answer is: the equilibrium  shifts toward the reactants, to the left side of chemical reaction.it is because lead(ii) nitrate dissociates in water: pb(no₃)₂ → pb²⁺(aq) + 2no₃⁻(aq).according to lechatelier's principle, the position of equilibrium moves to counteract thechange (more lead cations, common ion), the position of equilibrium will move so that the concentration ofproducts decrease and concentration of reactants of chemical reaction increase.read more on -