Flexible collodion contains 20% w/w camphor and 30% w/w castor oil. how many grams of each would be contained in 30 g of the mixture? (b) the specific gravity of castor oil is 0.955. how many milliliters of the oil is contained in 30 g of the mixture? (c) if the specific gravity of the mixture is 0.781, what are the percent w/v concentrations of lactic acid, salicylic acid, and trichloroacetic acid in the mixture?

The mass of each gram of camphor is 5 grams, and the mass of each gram of castor oil is 3.33 grams.

(a) The mass percentage has been the mass present in 100 grams of solution.

100 grams solution = 20 grams camphor

1 gram solution = 5 grams camphor.

100 grams solution = 30 grams castor oil

1 gram solution = 3.33 grams castor oil.

(b) Specific gravity has been the ratio of the density of a compound with water.

The density of water has been approximately equal to 1.

The specific gravity = density of compound.

The specific gravity of castor oil = density of castor oil.

0.955 g/ml = density of castor oil.

Density has been the ratio of mass to volume.

Density =

Mass of castor oil = 30 g.

Volume =

The volume of 30 grams castor oil =

The volume of 30 grams castor oil = 31.413 ml.

(c) From the specific gravity, the density of solution = 0.781 g/ml

For 100 g solution, volume of solution = 128.04 ml

The given mass of lactic acid = 4 g

Salicylic acid = 5 g

Trichloroacetic acid = 2 grams.

The percent concentration of w/v has been given by:

Percent composition =

Percent composition (w/v) Lactic acid = 3.124 %

Percent composition (w/v) Salicylic acid = 3.905 %

Percent composition (w/v) Trichloroacetic acid = 1.562 %

For more information about percent composition, refer to the link:

link

(a) The mass of camphor in 30 g of Flexible collodion = 6 g

The mass of castor oil in 30 g of Flexible collodion = 9 g

(b) 9.424 ml

(c) W/v concentration of Lactic acid in the mixture ≈ 3.12 %

W/v concentration of Salicylic acid in the mixture  ≈ 3.9 %

W/v concentration of Trichloroacetic acid in the mixture ≈ 1.56 %

Explanation:

(a) The given parameters are;

The percentage of camphor in Flexible collodion = 20%

The percentage of castor oil in Flexible collodion = 30%

Therefore, we have;

The mass of camphor in 30 g of Flexible collodion = 20/100 × 30 g = 6 g

The mass of castor oil in 30 g of Flexible collodion = 30/100 × 30 g = 9 g

(b) The given specific gravity of castor oil = 0.955

Therefore, the ratio of the density of castor oil to the density of water = 0.955

The density of water ≈ 1 g/ml

Therefore, the density of castor oil ≈ 0.955 × 1 g/ml = 0.955 g/ml

Density = Mass/Volume

∴ Volume = Mass/Density

The volume of the 9 grams of castor oil in the mixture = 9 g/(0.955 g/ml) = 9.424 ml

c. Given that the specific gravity of the mixture = 0.781, and the volume

We have;

The density of the mixture ≈ 0.781 × 1 g/ml = 0.781 g/ml

Whereby the content of Flexible collodion, by weight, includes;

Mass of Lactic acid per 100 g = 4 g

Mass of Salicylic acid  per 100 g = 5 g

Mass of Trichloroacetic acid per 100 g = 2 g

We have the volume of 100 g sample, = 100/0.781 ≈ 128.04 ml

Therefore; we have;

w/v concentration of Lactic acid in the mixture = 4/128.04×100 ≈ 3.12 %

w/v concentration of Salicylic acid in the mixture = 5/128.04×100 ≈ 3.9 %

w/v concentration of Trichloroacetic acid in the mixture = 2/128.04×100 ≈ 1.56 %.

the atomic number will stay the same no matter how many electrons it has, so it doesn’t decrease nor increase. it’ll only change with a different number of protons

consider the reaction below.

 no rx

at 500 k, the reaction is at equilibrium with the following concentrations.

[pci5]= 0.0095 m

[pci3] = 0.020

[ci2] = 0.020 m

what is the equilibrium constant for the given reaction?

0.042

0.42

2.4

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