Plz help me with this: Write the complete electron configuration, short hand electron configuration, and the orbital diagram. For the orbital diagram, use "u" for "upward arrow" and "d" for "downward arrow".
1) H
2) Ni
3) N
4) I and I^-1
5) Ca and Ca^+2
6) C
7) O and O^-2
8) Co
9) Ag and Ag^+1
10) Ar

We are to write the orbital notation and electronic configuration of sulfur and iron.

The orbital notation shows the filling of electrons into orbitals or sublevels.

Electron configuration  shows the distribution of electrons into shells;

       Number of electrons     Electron configuration     Orbital notation

S                  16                                   2 8 6                      1s² 2s² 2p⁶ 3s² 3p⁴

Fe                26                                2, 8, 14 2           1s² 2s² 2p⁶ 3s² 3p⁶3d⁶4s²        

Explanation:

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j