Be sure to answer all parts. Calculate the percent ionization of benzoic acid for the following concentrations: (a) 0.80 M, (b) 0.00080 M.

(a)

(b)

Explanation:

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In this case, since the ionization of benzoic acid produces benzoate and hydrogen ions:

Whose equilibrium expression is:

Whereas Ka is its acid ionization constant which equals 6.25x10⁻⁵, and each concentration can be expressed in terms of the reaction extent ():

In such a way, for the two given initial concentrations, 0.80 M and 0.00080 M we compute :

(a) 0.80 M

(b) 0.00080 M

Thus, the percent ionization for each case turns out:

(a)

(b)

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elements make up everything, and they combine to make compounds.

the answer is c

the dissociation of nickel hydroxide is follows:

the concentration of hydroxide ion is

the equilibrium constant value of nickel hydroxide is = 6.1 * 10^-^1^6 and thus equilibrium equation can be written as:

thus, concentration of ni is 0.23 * 10^-^4 mol /l