A gas has a volume of 100 mL and a pressure of 6 atm. What volume will the gas occupy when the pressure is reduced to 1 atm (total)?

We are given:

V1 = 100 mL          P1 = 6 atm

V2 = x mL             P2 = 1 atm

Solving for 'x' :

According to the Boyle's law:

P ∝ 1/V           (pressure and volume are inversely proportional)

PV = k            (where k is a constant)

since the constant k will be the same:

P1V1 = P2V2

replacing the variables

6 * 100 = 1 * x

x = 600 mL   OR   0.6L

Therefore, the gas will have a volume of 600mL or 0.6L

i'm pretty sure its b i might be wrong though!