Ireally need on this question!
the spectrophotometer really measures the percent of light that is transmitted through the solution. the instrument then converts %t (transmittance) into absorbance by using the equation you determined in the pre-lab section. if the absorbance of a sample is 0.85, what is the percent light transmitted through the colored sample at this collected wavelength?

we only used the spectrophotometer to measure the absorbance and never got any %t values. so i have to convert absorbance to transmittance. how do i do this with the given absorbance of 0.85?

14.12% the percent light transmitted through the colored sample at this collected wavelength.

Explanation:

Formula used to convert absorbance into transmittance is:

where,

A = absorbance of solution

T = Transmittance

= incident light

= transmitted light

Given = A = 0.85

Percentage of light transmitted to color solution:

14.12% the percent light transmitted through the colored sample at this collected wavelength.

answer: option (4) is the correct answer.

explanation:

areas which are at low altitudes and near the equator tend to receive direct sunlight from the sun. hence, heat energy or radiations from the sun make these areas warmer and they have warmest water.

whereas areas which are at high altitudes and away from the equator do no receive direct sunlight. hence, no direct contact from the sun makes these regions colder and thus, they have colder water.

thus, we can conclude that the statement areas at low latitudes near the equator have the warmest water because they receive the most direct sunlight best explains the relationship between an area's geography and the temperature of its surface water.

specific gravity is the density of a substance divided by the density of water. since (at standard temperature and pressure) water has a density of 1 gram/cm3, and since all of the units cancel, specific gravity is usually very close to the same value as density

so "c" is the answer

plz give brainliest