The pressure of 8.40 L of nitrogen gas in a flexible container is decreased to one-half its original pressure, and its absolute temperature is increased to double the original temperature. What is the new volume?

33.6 L

Explanation:

From the question given above, the following data were obtained from:

Initial volume (V1) = 8.40 L L

Initial pressure (P1) = P

Initial temperature (T1) = T

Final pressure (P2) = one-half the original pressure = ½P

Final temperature (T2) = double the original temperature = 2T

Final volume (V2) =.?

Thus, the new volume of the gas can be obtained as follow:

P1V1/ T1 = P2V2 /T2

P × 8.40 / T = ½P × V2 /2T

P × 8.40 / T = P × V2 / 4T

Cross multiply

T × P × V2 = P × 8.40 × 4T

Divide both side by T × P

V2 = (P × 8.40 × 4T) /T × P

V2 = 8.40 × 4

V2 = 33.6 L

Thus, the new volume of the gas is 33.6 L

a is the correct answer