7. The gas in a balloon occupies 2.25L at 38C. Wat what temperature will the balloon expand to 3.50L?

T₂ = 483.8 K

Explanation:

Given data:

Initial volume of balloon = 2.25 L

Initial temperature = 38°C (38+273= 311 K)

Final temperature = ?

Final volume = 3.50 L

Solution:

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

T₂ = V₂T₁/V₁  

T₂ = 3.50 L × 311 K / 2.25 L

T₂ = 1088.5 L.K / 298 K

T₂ = 483.8 K

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