B. How many grams of C6H1206 are needed to form 7.50 g of C2H5OH?

THINK IT"S

Molar mass C2H5OH = 46 g / mol

7.50 g / 46 = 0.163 moles

the ratio between C6H12O6 and C2H5OH is 1 : 2

1 : 2 = x : 0.163

x = 0.0815 moles of C6H12O6 needed

molar mass C6H12O6 = 180 g/mol

180 x 0.0815 = 14.7 g

2b2t

explanation:

2b2t

the density of gold = 19.3 g/cm3

the relation between density and mass and volume is

density = mass / volume

given :

mass of gold = 13 g

density = 13g / volume = 19.3

volume = 13 /19.3 = 0.67 cm^3

thus volume of gold nugget = 0.67 cm^3