I have added 12.0 L of air. To a balloon at sea level(760 torr). If I take the ballon with me to Colorado, where the air pressure is 0.650 atm, what will the new volume of the balloon be?

18.46 L

Explanation:

From the question given above, the following data were obtained:

Initial volume (V1) = 12.0 L

Initial pressure (P1) = 760 torr

Final pressure (P2) = 0.650 atm

Final volume (V2) =..?

Next, we shall express the pressure in the same unit of measurement.

Thus, 760 torr is equivalent to 1 atm.

Finally, we shall the new volume of the balloon as follow:

Initial volume (V1) = 12.0 L

Initial pressure (P1) = 1 atm

Final pressure (P2) = 0.650 atm

Final volume (V2) =..?

P1V1 = P2V2

1 × 12 = 0.650 × V2

12 = 0.650 × V2

Divide both side by 0.65

V2 = 12/0.65

V2 = 18.46 L

Therefore, the new volume of the balloon is 18.46 L.

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