A 1.90-g sample of an oxide of bromine is converted to 3.188 g of AgBr. Calculate the empirical formula of the oxide. (molar mass for AgBr =187.78 g/mol) a. BrO
b. Br2O
c. BrO
d. BrO3
e. None of these

e. None of these

Explanation:

The oxide of Bromine (BrₐOₓ) produce "a" moles of Br that are equal to "a" moles of AgBr. The moles of AgBr are:

Moles AgBr:

3.188g AgBr * (1mol / 187.78g) = 0.01698 moles of AgBr = Moles of Br

These moles of Br weighs (Molar mass: 79.9g/mol):

0.01698 moles of Br * (79.9g / mol) = 1.36g of Br

Mass of Oxygen must be:

1.90g - 1.36g Br = 0.54g oxygen. In moles:

0.54g O * (1mol / 16g) = 0.03375 moles of O

Empirical formula is the simplest ratio of atoms in the molecule. Dividing in the moles of Br:

Br:  0.01698 moles of Br / 0.01698 moles = 1

O: 0.03375 moles of O / 0.01698 moles = 1.99 ≅ 2

That means empirical formula is:

BrO₂

And right option is:

when atmosphere interacts with biosphere they focuses on on the sources and sinks of green house gases (ghgs) air pollutants, particular matters, water and energy between the earth's surface and the atmosphere. the biosphere affects the climate. the atmosphere and biosphere are in constant interaction with each other, and all living things rely on gases in the atmosphere for life. organisms such as animals take in oxygen gas form the atmosphere to use in every cell of their body for smooth functioning of daily routine exercises.