When 11.0g of Mg(s) reacts with excess water to produce 5.75g of Mg(OH)2, what is the percent yield of the reaction

The chemical equation is given by :

From above equation :

24 gm Mg forms -----> 58 gm of

So, 11 g of Mg will form = .

Now, percentage yield is given by :

Therefore, the percentage yield is given by 21.63%.

Hence, this is the required solution.