4.60 g of 3-hexanol were obtained from 5.33 g of hex-3-ene. Determine the percentage yield of 3-hexanol. a Determine the moles of hex-3-ene, , used in the experiment. (To avoid introducing rounding errors on intermediate calculations, enter your answer to four significant figures.)

Explanation:

C₆H₁₂     + H₂O      =     C₆H₁₃OH

hexene                      hexanol

1 mole                             1 mole  

Mol weight of hexene = 84

Mol weight of hexanol   = 102

5.33g of hexene = .06345 moles

4.6 g of hexenol = .0451 moles

percentage yield of hexanol

= .0451 x 100 / .06345

= 71.07 %

Moles of hexene used = .0451 moles

for step 7 table c on the lab "newtons law of action"   the average time it took the car to travel .25 meters   was 1.92 seconds.

the average time it took the car to travel 0.50 meters was 2.61 seconds

hope this : )

it’s previous models   because when i picked that son of a gun’s answer it was wrong look for previous models because they might make it a different letter