What is the percent m/m concentration of an aqueous solution of sodium nitrate in which there are 24.34 grams of solute in 138.87 grams of solvent

14.9%m/m

Explanation:

The percent m/m concentration of a solution (%m/m) indicates the grams of solute there are in 100 g of solution. It can be calculated as follows:

%m/m= mass of solute(g)/mass of solution(g) x 100

As the solution is composed by solute + solvent, the mathematical expression can be transformed in:

%m/m= mass of solute(g)/(mass of solute + mass of solvent (g) )x 100

         = 24.34 g/(24.34 g + 138.87 g) x 100

         = 24.34 g/(163.21 g) x 100

         = 14.9%

c, liquids evaporate, creating a gas

water at room temperature is flowing through a pipe with pressure taps located 10 ft apart along one section of the pipe, which are connected to a mercury (s=13.6) manometer.