CHEMISTRY PLEASE HELP> ENTHALPY Consider the enthalpy diagram shown below.

a. According to the enthalpy change, would you expect the reaction represented by the diagram to be thermodynamically favorable or unfavorable? Explain. (1 point)

b. Describe a way in which such a reaction might produce large amount of product, despite being thermodynamically unfavorable. (1 point)

c. Consider the reverse reaction, in which the products become the reactants and the reactants become the products. What effect, if any, would this have on the reaction's thermodynamic favorability, the energy of the reaction, and the graph? (2 points)

answer: the rate of diffusion increases with increase in temperature.

increase in temperature, increases the molecular/particles speed (kinetic energy. diffusion means movement of particles through the material.

generally, the heavier the particle the more it interacts with the environment and more the temperature matters. so higher temperature results in higher diffusion.

1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%

the answer is c i took the test

c. 4.54 x 10–12 j happens to be correct