at standard pressure, the total amount of heat required to completely vaporize a 100- gram sample of water at its boiling point is? no

The correct answer is - 2.26*10^5 J

Explanation:

Given:

The amount of water need to vaporized = 100 g

We know:

The heat of vaporization of water = 2260 j/g

The required heat (q)

= mass of the liquid (m) * the heat of vaporization of liquid (ΔH)

q = m*ΔH 1

So, from the equation 1,

the 100 gram sample of water being completely vaporized needs

= 2260*100

=2.26*10^5 J.

Thus, the correct answer is = 2.26*10^5 J.

the answer is minerals.