In Universe L, recently discovered by an intrepid team of chemists who also happen to have studied interdimensional travel, quantum mechanics works just as it does in our universe, except that there are three d orbitals instead of the usual number we observe here. Use these facts to write the ground-state electron configurations of the second and third elements in the first transition series in Universe L. Note: you may use X to stand for the electron configuration of the noble gas at the end of the row before the first transition series. second transition metal: third transition metal:

Follows are the solution to this question:

Explanation:

The law of dogs:

Under such a law, although electrons were filled in the

electron, a computer terminal is loaded into it's orbital or paired.

All particles should have the same spinning as one another.

Principle of building construction:

By this principle, atoms are filled with both the energy equation in the angular first. Three d-orbitals exist in cosmos L.

The very first series of transition metals show divergence from the dog law and the principle of Aufbau.

Besides that, half - or full-filled orbital angular momentum is much more stable than orbitally filled up. Components thus strive to achieve equilibrium through transferring electrons, as was shown below partially  filled:

please find the attaced file.

Its second transition element (such that, titanium) is thus the electrical structure in the universe L. besides half-filled stable setup since only 3 d, orbital angular is filled present.

Its third transition factor (Vanadium) electronically does have a configuration of , It's half-full already. where X sits only at end of the row for noble gas Before the first sequence for transformations.

number of molecules / avogadro's number * molecule molecular = mass

explanation:

we define a gram-molecular weight as the mass of one mole of any element or compound. a mole contains avogadro's number of units (molecules) –  

6.022

x

10

23

. so, dividing the number of molecules by avogadro's number gives us the number of moles. multiplying that by the molecular weight gives us the mass. from the periodic table we find the gram-molecular weight of u to be238 and of f to be19. so,  

u

f

6

will have a gram-molecular weight of 352g.

atomic mass = 39

number of neutrons = 20

number of protons= 19

electronic configuration = 1s2 2s2 2p6 3s2 3p6 4s1

the number of electron in first shell = 2

number of electrons in n=3 shell = 8