A sample of oxygen gas initially at 303 K was heated to 357 K. If the volume of the oxygen gas sample at 357 K is 765.9 mL, what was its volume at 303 K? V= mL

650.04 mL

Explanation:

It is given that,

The volume of the oxygen gas sample at 357 K is 765.9 mL. We need to find the volume of the sample at 303 K.

We know that, the volume is directly proportional to the temperature at constant pressure. It is Charles's law. Its mathematical form is given by :

We have, V₁ = 765.9 mL, T₁ = 357 K, T₂ = 303 K, V₂ =?

Putting all the values,

So, at 303 K, the volume is 650.04 mL.

a 20-cm-long, cylindrical graphite (pure carbon) rod is inserted into an oxidizing atmosphere at 1145 k and 1.013 x 105 pa pressure. the oxidizing process is limited by the diffu- sion of oxygen counterflow to the carbon monoxide that is formed on the cylindrical surface.

answer: they produce more slow than unicellular organisms.