Consider the following chemical reaction: Mg + F2 -> MgF2 When 24.3 g of Mg react with 38.0 grams of F2, then:
a) how many grams of MgF2 will be obtained?
b) how many grams of Mg are present in the product MgF2?

Explanation:

Mg    +   F₂   ->    MgF₂

1 mole    1 mole       1 mole

24.3 g of Mg = 24.3 / 24.3 = 1 mole of Mg

38 grams of F₂ = 38 /38 = 1 mole of F₂

So 1 mole of Mg reacts with 1 mole of F₂ to give one mole of MgF₂

MgF₂ produced = 1 mole = 62.3 grams

b )

Mg present in 62.3grams of product = 24.3 grams .

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i believe the answer is 5,000