What is the net ionic equation of CuBr2+Na2S=CuS+2NaBr?

.

Explanation:

Start by identifying the solubility of each species in the original chemical equation:

. (Balanced.)

Rewrite species that exist as ions as the corresponding ions to obtain an ionic equation for this reaction. Those species include:

In particular:

Species that do not ionize in water ( in this question) should not be rewritten. Hence, the ionic equation will be:

.

Eliminate ions that appear on both sides of the equation to obtain a net ionic equation. In this ionic equation, those ions include:

Hence, the net ionic equation will be:

.

you need to take a look at the periodic system in order to sort these elements into pairs that would most likely exhibit similar chemical properties. first, you need to find elements that are found in the same group (groups are vertical in the periodic system), and then to see whether they have the same valence number. if they meet these criteria, they will have similar properties.

the first pair: ne (neon) and kr (krypton), are noble gases found in group 8

the second pair: li (lithium) and k (potassium), found in group 1

the third pair: s (sulfur) and te (tellurium), found in group 6

a pan containing water is placed in a positio n where it is exposed to a 10 mile per hour wind. the pan contains a uniform depth of 1.27 cm of water, is quite wide, and has a length of 2.44 m in the wind direction. the water in the pan is at a constant temperature of 15.5 °c.