A liquid is exposed to infrared radiation with a wavelength of 5.10×10−4 cm. Assume that all the radiation is absorbed and converted to heat. How many photons are required for the liquid to absorb 42.75 J
of heat?

1.1×10²¹ photon

Explanation:

Given data:

Wavelength of radiation = 5.10×10⁻⁴ cm

How many radiations required to liquid inorder to absorbed 42.75 J = ?

Solution:

First of all we will calculate the energy of radiation having 5.10×10⁻⁴ cm.

E = h.c/ λ

E = 6.63 ×10⁻³⁴ js  × 3 ×10⁸ m/s / 0.051×10⁻⁴ m

E = 19.89 ×10⁻²⁶ j.m/ 0.051×10⁻⁴ m

E = 390 ×10⁻²² j

The energy of 1 photon with  5.10×10⁻⁴ cm. wavelength having 390 ×10⁻²² j energy.

1 photon × 42.75 J/390 ×10⁻²² j

0.11 ×10²²photon

1.1×10²¹ photon

for step 7 table c on the lab "newtons law of action"   the average time it took the car to travel .25 meters   was 1.92 seconds.

the average time it took the car to travel 0.50 meters was 2.61 seconds

hope this : )