Bi2O3 (s) + 3 CO (g) → 2 Bi (s) + 3 CO2 (g) Datos:
S° Bi2O3 (s) = 151,5 J/mol K
S° CO (g) = 197,7 J/mol K
S° Bi (s) = 56,7 J/mol K
S° CO2 (g) = 213,7 J/mol K
Calcular cambio de entropia y si se puede explicar mejor

The answer is 4 i don't know if its right let me see.

Im not sure but if i figure it out i’ll hello you

Heat capacity = mcδtheat capacity = 2.676×10^3 j ..the heat capacity given is for 7.00 g of kcn,potassium cyanide which is equal to 0. mole of mole = mass  ÷ mr of kcn is 7  ÷ 65 =0.therefore: 0. of kcn liberates 2.676×10^3 j of heat1 mole   (2.676×10^3    ÷  0.107 )  × 1 =do the calculation to obtain 25009 j = 25kj