Can someone solve this? ill give brainliest or however you spell it. 16 g CH4 + 64 g O2 → 44 g CO2 + 36g H2O

Given that 16 g CH4 + 64 g 02 - 44 g CO2 + 36g H2O

To explain the law of conservation of mass and describe how the equation represents the law of conservation of mass, let me first start from law.

The law state that: mass can neither be created nor destroyed.

The mass of each element at the reaction side must be equal or the Same with the magnitude of mass at the product

The equation represents the law of conservation of mass because the mass of molecules at the right hand side is equal to or balance with the molecules at the left hand side. For example, the number of Oxygen, and othe elements are the at both side.

CH4(g) + 2O2(g)→ CO2(g) + 2H2O(g) Which ... Since 1 mole methane = 12+4×1=16 g and 2 mole oxygen =2×32=64 g, ... 1 molecule or 16 g) of CH4 reacts with 2 moles or 2 molecules or 64 g of ... or 1 molecule or 44 g of CO2 and 2 mole or 2 molecules or 36 g of water.

Explanation:

here is a combustion of methane bc im stupid

sorry i was late, but i don't know what assignment your talking about, i'm in flvs as well, im in earth space science. but u are behind pace bc every class should be in the 3's or 4'

let that person have a turn to speak : )