calculate the mass percent composition of a mixture that contains 26 grams of copper and 79 grams of silver

Explanation:

Mass percentage composition of copper and silver in the mixture will be calculated differently, sum of which must be equal to 100 to show the calculation is right.

To determine the percentage, one must first add the sum of the two masses together 26 + 79 = 105 g

If the mass of copper is 26 g, % by mass of copper = 26/105 × 100

mass percent of copper = 24.76%

If the mass of silver is 79 g, % by mass of silver = 79/105 × 100

mass percent of silver = 75.24%

NOTE: To show the calculation is right 24.76 + 75.24 = 100

in the given question, the partial pressure is calculated by using the ideal gas equation, that is, pv = nrt

here, p is pressure, v is volume = 25 l, n is number of moles = 0.0104 moles, r is gas constant = -0.0821 l.atm / mol.k

t is temperature = 273 k

p = nrt / v

p = (0.0104 mol × 0.0821 l.atm / mol.k × 273 k) / 25 l

= 0.0093 atm