Cobalt-60 is an artificial radioisotope that is produced in a nuclear reactor for use as a gamma-ray source in the treatment of certain types of cancer. If the wavelength of the gamma radiation from Co-60 is 2.00 x 10-12 m, calculate the energy of a photon of this radiation.

E = 9.93 x 10^-14 J

Explanation:

Wavelength, λ = 2.00 x 10-12 m

Energy, E = ?

Relationship between both quantities is given as;

E = hc/λ

where;

c = speed of light = 2.998  ×  10 8  m⋅s −1

h = Plank's constant = 6.626*10-34 Js

Solving for E;

E = 6.626*10^-34 * 2.998  ×  10^ 8 / 2.00 x 10^-12

E = 9.93 x 10^-14 J

the answer is the first option

explanation:

just googled it m8. not that hard

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distance, luminosity, brightness, radius, chemical composition, and temperature