The pH of a solution of 4-chlorobutanoic acid is measured to be . Calculate the acid dissociation constant of 4-chlorobutanoic acid. Round your answer to significant digits.

Explanation:

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In this case, as you are not indicating the molarity of the solution and its pH we are going to assume they are 1.4 M and 2.19 respectively as typical problems over this. In such a way, based on the pH we can compute the concentration of hydrogen ions in the solution:

Next, the dissociation of 4-chlorobutanoic acid is:

Since it is a weak acid, therefore, its equilibrium expression is:

Since the concentration of hydrogen ions equal the concentration of 4-chlorobutanoate ions at equilibrium and the concentration the 4-chlorobutanoic acid equals 1.4 M minus the concentration of hydrogen ions, which is related to the reaction extent , the acid dissociation constant is:

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metals are good conductor of electricity. it has free electrons on their surface. according to electron pool theory, each atom present in a metal crystal losses all of its valence electron and as a result a pool of free is form. these pool of electrons are free to move and   conduct electricity easily   while making metal as good conductor.

the correct answer is a. the ability of electrons to flow throughout the metal.

if it's not useful, feel free to report for mistake in answer.

percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally