Given these reactions, X(s)+12O2(g)⟶XO(s)Δ=−954.5 kJ/molXCO3(s)⟶XO(s)+CO2(g)Δ=+378.1 kJ/mol X ( s ) + 1 2 O 2 ( g ) ⟶XO ( s ) Δ H=−954.5 kJ / mol XCO 3 ( s ) ⟶XO ( s ) + CO 2 ( g ) Δ H=+378.1 kJ / mol what is Δ Δ H for this reaction? X(s)+12O2(g)+CO2(g)⟶XCO3(s) X ( s ) + 1 2 O 2 ( g ) + CO 2 ( g ) ⟶ XCO 3 ( s )

ΔH = -1332,5 kJ/mol

Explanation:

The general equation of the enthalpy of reaction is:

AB + CD → AC + BD

ΔH =( ΔH(AC) + ΔH(BD) ) - (ΔH(AB) + ΔH(CD) )

To simplify the equations, the states of aggregation can be omitted here.

So the first equation is:

X + 12 O2 → XO     | ΔH = -954,5 kJ/mol

The equation of the enthalpy of reaction is thus:

-954,5 kJ/mol = ΔH(XO) - ( ΔH(X) + 12*ΔH(O2) )

Since the enthalpy of reaction of all pure elements is 0, the equation can be simplified:

-954,5 kJ/mol = ΔH(XO) - ( 0 + 12*0 )

ΔH(XO) = -954,5 kJ/mol

The next equation is:

XCO3 → XO + CO2    | ΔH = +378,1 kJ/mol

The equation of the enthalpy of reaction is thus:

+378,1 kJ/mol = ( ΔH(XO) + ΔH(CO2) ) - ΔH(XCO3)

+378,1 kJ/mol = -954,4 kJ/mol + ΔH(CO2) - ΔH(XCO3)

+1332,5 kJ/mol = ΔH(CO2) - ΔH(XCO3)

X + 12 O2 + CO2 → XCO3

The equation of the enthalpy of reaction is thus:

ΔH = ΔH(XCO3) - ΔH(CO2)

ΔH = -1332,5 kJ/mol

distance, luminosity, brightness, radius, chemical composition, and temperature

on passing the small ampere of electric current through the tube made of ar and hg of cfl generates uv rays which excites the fluorescent and thus emits the high radiation by consumption of just 5- 12 w in comparison to incandescent light which requires more power such as around 40 - 55 w to lighten.

moreover the life span of fluorescent or cfl is around 8000 h whereas the life span of incandescent is around 1200 h

hence, the building installed with incandescent lights bears more electricity bill.