Lanthanum emits gamma radiation with a wavelength of 1.24 x 10-31 meters. How much energy is in this gamma ray?

e = 1.60x10⁶J

Explanation:

It is possible to find the energy from the wavelength of the radiation as follows:

e = c*h / λ

Where e is energy in joules

c is light velocity (3.0x10⁸m/s)

h is Planck's constant (6.626x10⁻³⁴Js)

And λ is wavelength in meters (1.24x10⁻³¹m)

e = 3.0x10⁸m/s*6.626x10⁻³⁴Js / 1.24x10⁻³¹m

in scientific notation, the value of the  speed of light in a vacuum

  will be written as 2.995 * 10^8. when this value is represented in the form of

  a * 10^b, then, a = 2.995 and b = 8.

the value of the speed of light in a vacuum given above can also be rounded up to approximately 300000000. in this case, the scientific notation will be written as 3 *10^8.