Write the nuclear equation for the release of a beta particle by 22888Ra

The nuclear equation :

₈₈Ra²²⁸ ⇒ ₋₁e⁰ + ₈₉Ac²²⁸

Radioactivity is the process of unstable isotopes to stable isotopes by decay, by emitting certain particles,  

The sum of the mass number and atomic number before and after decay is the same

Ra = Radium ⇒alkaline earth, group 2, block s, period 7

Atomic mass = 88

If an element releases an β ₋₁e⁰,  the atomic number of the new element increases by 1

The new element will have an atomic number: 88+1=89 and mass number 288

The element having the atomic number 89 is Actinium(Ac)

So the nuclear equation :

₈₈Ra²²⁸ ⇒ ₋₁e⁰ + ₈₉Ac²²⁸

b) mutualism

hope this : )

< > according to newton's third law of motion, forces always act in equal but opposite pairs. another way of saying this is for every action, there is an equal but opposite reaction.< >