.What is the empirical formula for each of the following:a) C6H12O6b) Na2C2O4c) Na3PO4d) C2H4O27.Name the abovecompounds. a)b)c)d) g

Explanation:

Empirical formula is the forrmula that shows the relative number of atoms present in a compound. It is also referred to as the simplest formular of a compound.

a) C6H12O6

The atoms of the elements present are in ratio; 6:12:6

After simplifying by dividing by the highest common factor (6) we have;

6/6 : 12/6 : 6/6 = 1 : 2 : 1

The empirical formula is CH2O

b) Na2C2O4

The atoms of the elements present are in ratio; 2:2:4

After simplifying by dividing by the highest common factor (2) we have;

2/2 : 2/2 : 4/2 = 1 : 1 : 2

The empirical formula is NaCO2

c)  Na3PO4

The atoms of the elements present are in ratio; 3:1:4

After simplifying by dividing by the highest common factor (1) we have;

3/1 : 1/1 : 4/1 = 3 : 1 : 4

The empirical formula is still Na3PO4.

d) C2H4O2

The atoms of the elements present are in ratio; 2:4:2

After simplifying by dividing by the highest common factor (1) we have;

2/2 : 4/2 : 2/2 = 1 : 2 : 1

The empirical formula is CH2O

The names are;

a) Glucose

b) Sodium Oxalate

c) Trisodium Phosphate

d) Acetic Acid

answer : third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol

explanation :

let us write down the given equations

equation 1 :

equation 2 :

equation 3 :

let us use hess's law to find out which 2 equations can be added to get the third equation.

let us reverse equation 2 and multiply it by 2. the new equation that we get is,

equation 4 :

let us add equation 1 & 4

the above equation is similar to equation 3 but has different value for dhrxn.

therefore third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol